You have a sequence $$$a$$$ with $$$n$$$ elements $$$1, 2, 3, \dots, k - 1, k, k - 1, k - 2, \dots, k - (n - k)$$$ ($$$k \le n \lt 2k$$$).

Let's call as inversion in $$$a$$$ a pair of indices $$$i \lt j$$$ such that $$$a[i] \gt a[j]$$$.

Suppose, you have some permutation $$$p$$$ of size $$$k$$$ and you build a sequence $$$b$$$ of size $$$n$$$ in the following manner: $$$b[i] = p[a[i]]$$$.

Your goal is to find such permutation $$$p$$$ that the total number of inversions in $$$b$$$ doesn't exceed the total number of inversions in $$$a$$$, and $$$b$$$ is lexicographically maximum.

Small reminder: the sequence of $$$k$$$ integers is called a permutation if it contains all integers from $$$1$$$ to $$$k$$$ exactly once.

Another small reminder: a sequence $$$s$$$ is lexicographically smaller than another sequence $$$t$$$, if either $$$s$$$ is a prefix of $$$t$$$, or for the first $$$i$$$ such that $$$s_i \ne t_i$$$, $$$s_i \lt t_i$$$ holds (in the first position that these sequences are different, $$$s$$$ has smaller number than $$$t$$$).

Input

The first line contains a single integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases.

The first and only line of each test case contains two integers $$$n$$$ and $$$k$$$ ($$$k \le n \lt 2k$$$; $$$1 \le k \le 10^5$$$) — the length of the sequence $$$a$$$ and its maximum.

It's guaranteed that the total sum of $$$k$$$ over test cases doesn't exceed $$$10^5$$$.

Output

For each test case, print $$$k$$$ integers — the permutation $$$p$$$ which maximizes $$$b$$$ lexicographically without increasing the total number of inversions.

It can be proven that $$$p$$$ exists and is unique.

Note

In the first test case, the sequence $$$a = [1]$$$, there is only one permutation $$$p = [1]$$$.

In the second test case, the sequence $$$a = [1, 2]$$$. There is no inversion in $$$a$$$, so there is only one permutation $$$p = [1, 2]$$$ which doesn't increase the number of inversions.

In the third test case, $$$a = [1, 2, 1]$$$ and has $$$1$$$ inversion. If we use $$$p = [2, 1]$$$, then $$$b = [p[a[1]], p[a[2]], p[a[3]]] = [2, 1, 2]$$$ and also has $$$1$$$ inversion.

In the fourth test case, $$$a = [1, 2, 3, 2]$$$, and since $$$p = [1, 3, 2]$$$ then $$$b = [1, 3, 2, 3]$$$. Both $$$a$$$ and $$$b$$$ have $$$1$$$ inversion and $$$b$$$ is the lexicographically maximum.

No More Inversions

Examples