After defeating a Blacklist Rival, you get a chance to draw $$$1$$$ reward slip out of $$$x$$$ hidden valid slips. Initially, $$$x=3$$$ and these hidden valid slips are Cash Slip, Impound Strike Release Marker and Pink Slip of Rival's Car. Initially, the probability of drawing these in a random guess are $$$c$$$, $$$m$$$, and $$$p$$$, respectively. There is also a volatility factor $$$v$$$. You can play any number of Rival Races as long as you don't draw a Pink Slip. Assume that you win each race and get a chance to draw a reward slip. In each draw, you draw one of the $$$x$$$ valid items with their respective probabilities. Suppose you draw a particular item and its probability of drawing before the draw was $$$a$$$. Then,

If the item was a Pink Slip, the quest is over, and you will not play any more races.
Otherwise,
1. If $$$a\leq v$$$, the probability of the item drawn becomes $$$0$$$ and the item is no longer a valid item for all the further draws, reducing $$$x$$$ by $$$1$$$. Moreover, the reduced probability $$$a$$$ is distributed equally among the other remaining valid items.
2. If $$$a \gt v$$$, the probability of the item drawn reduces by $$$v$$$ and the reduced probability is distributed equally among the other valid items.

For example,

If $$$(c,m,p)=(0.2,0.1,0.7)$$$ and $$$v=0.1$$$, after drawing Cash, the new probabilities will be $$$(0.1,0.15,0.75)$$$.
If $$$(c,m,p)=(0.1,0.2,0.7)$$$ and $$$v=0.2$$$, after drawing Cash, the new probabilities will be $$$(Invalid,0.25,0.75)$$$.
If $$$(c,m,p)=(0.2,Invalid,0.8)$$$ and $$$v=0.1$$$, after drawing Cash, the new probabilities will be $$$(0.1,Invalid,0.9)$$$.
If $$$(c,m,p)=(0.1,Invalid,0.9)$$$ and $$$v=0.2$$$, after drawing Cash, the new probabilities will be $$$(Invalid,Invalid,1.0)$$$.

You need the cars of Rivals. So, you need to find the expected number of races that you must play in order to draw a pink slip.

Input

The first line of input contains a single integer $$$t$$$ ($$$1\leq t\leq 10$$$) — the number of test cases.

The first and the only line of each test case contains four real numbers $$$c$$$, $$$m$$$, $$$p$$$ and $$$v$$$ ($$$0 \lt c,m,p \lt 1$$$, $$$c+m+p=1$$$, $$$0.1\leq v\leq 0.9$$$).

Additionally, it is guaranteed that each of $$$c$$$, $$$m$$$, $$$p$$$ and $$$v$$$ have at most $$$4$$$ decimal places.

Output

For each test case, output a single line containing a single real number — the expected number of races that you must play in order to draw a Pink Slip.

Your answer is considered correct if its absolute or relative error does not exceed $$$10^{-6}$$$.

Formally, let your answer be $$$a$$$, and the jury's answer be $$$b$$$. Your answer is accepted if and only if $$$\frac{|a - b|}{\max{(1, |b|)}} \le 10^{-6}$$$.

Note

For the first test case, the possible drawing sequences are:

P with a probability of $$$0.6$$$;
CP with a probability of $$$0.2\cdot 0.7 = 0.14$$$;
CMP with a probability of $$$0.2\cdot 0.3\cdot 0.9 = 0.054$$$;
CMMP with a probability of $$$0.2\cdot 0.3\cdot 0.1\cdot 1 = 0.006$$$;
MP with a probability of $$$0.2\cdot 0.7 = 0.14$$$;
MCP with a probability of $$$0.2\cdot 0.3\cdot 0.9 = 0.054$$$;
MCCP with a probability of $$$0.2\cdot 0.3\cdot 0.1\cdot 1 = 0.006$$$.

So, the expected number of races is equal to $$$1\cdot 0.6 + 2\cdot 0.14 + 3\cdot 0.054 + 4\cdot 0.006 + 2\cdot 0.14 + 3\cdot 0.054 + 4\cdot 0.006 = 1.532$$$.

For the second test case, the possible drawing sequences are:

P with a probability of $$$0.4$$$;
CP with a probability of $$$0.4\cdot 0.6 = 0.24$$$;
CMP with a probability of $$$0.4\cdot 0.4\cdot 1 = 0.16$$$;
MP with a probability of $$$0.2\cdot 0.5 = 0.1$$$;
MCP with a probability of $$$0.2\cdot 0.5\cdot 1 = 0.1$$$.

So, the expected number of races is equal to $$$1\cdot 0.4 + 2\cdot 0.24 + 3\cdot 0.16 + 2\cdot 0.1 + 3\cdot 0.1 = 1.86$$$.

Need for Pink Slips

Examples