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Theofanis has a riddle for you and if you manage to solve it, he will give you a Cypriot snack halloumi for free (Cypriot cheese).

You are given an integer $$$n$$$. You need to find two integers $$$l$$$ and $$$r$$$ such that $$$-10^{18} \le l \lt r \le 10^{18}$$$ and $$$l + (l + 1) + \ldots + (r - 1) + r = n$$$.

Input

The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases.

The first and only line of each test case contains a single integer $$$n$$$ ($$$1 \le n \le 10^{18}$$$).

Output

For each test case, print the two integers $$$l$$$ and $$$r$$$ such that $$$-10^{18} \le l \lt r \le 10^{18}$$$ and $$$l + (l + 1) + \ldots + (r - 1) + r = n$$$.

It can be proven that an answer always exists. If there are multiple answers, print any.

Note

In the first test case, $$$0 + 1 = 1$

Consecutive Sum Riddle

Examples