Second Dark Matter Battle - Pokemon Super Mystery Dungeon

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Bessie has recently started playing a famous card game. In the game, there is only one deck of cards, consisting of $$$a$$$ "draw $$$0$$$" cards, $$$b$$$ "draw $$$1$$$" cards, $$$c$$$ "draw $$$2$$$" cards, and $$$5$$$ special cards. At the start of the game, all cards are in the randomly shuffled deck.

Bessie starts the game by drawing the top $$$5$$$ cards of the deck. She may then play "draw $$$x$$$" cards from the hand to draw the next $$$x$$$ cards from the top of the deck. Note that every card can only be played once, special cards cannot be played, and if Bessie uses a "draw $$$2$$$" card when there is only $$$1$$$ card remaining in the deck, then she simply draws that remaining card. Bessie wins if she draws all $$$5$$$ special cards.

Since Bessie is not very good at math problems, she wants you to find the probability that she wins, given that the deck is shuffled randomly over all $$$(a + b + c + 5)!$$$ possible orderings. It can be shown that this answer can always be expressed as a fraction $$$\frac{p}{q}$$$ where $$$p$$$ and $$$q$$$ are coprime integers. Output $$$p \cdot q^{-1}$$$ modulo $$$998\,244\,353$$$.

Input

The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases.

Each test case contains three integers $$$a$$$, $$$b$$$, and $$$c$$$ ($$$0 \le a, b, c \le 2 \cdot 10^5$$$) – the number of draw $$$0$$$ cards, draw $$$1$$$ cards, and draw $$$2$$$ cards, respectively.

It is guaranteed that the sum of $$$a$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$, the sum of $$$b$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$, and the sum of $$$c$$$ over all test cases does not exceed $$$2 \cdot 10^5$$$.

Output

For each test case, output a single integer — the probability that Bessie wins, modulo $$$998\,244\,353$$$.

Note

In the first case, we have $$$1$$$ of each type of "draw" card and $$$5$$$ special cards. There are $$$30\,720$$$ starting decks where Bessie will win by drawing the top $$$5$$$ cards and $$$40\,320$$$ starting decks in total. Thus, the probability of Bessie winning is $$$\frac{30\,720}{40\,320} = \frac{16}{21}$$$.

One example of a winning starting deck is, top to bottom,

"Special",
"Draw $$$1$$$",
"Special",
"Special",
"Draw $$$0$$$",
"Draw $$$2$$$",
"Special",
"Special".

One example of a losing starting deck is:

"Special",
"Draw $$$1$$$",
"Special",
"Special",
"Draw $$$0$$$",
"Special",
"Special",
"Draw $$$2$$$".

Bessie and Cards

Examples