Serega loves fun. However, everyone has fun in the unique manner. Serega has fun by solving query problems. One day Fedor came up with such a problem.

You are given an array a consisting of n positive integers and queries to it. The queries can be of two types:

Make a unit cyclic shift to the right on the segment from l to r (both borders inclusive). That is rearrange elements of the array in the following manner:a[l], a[l + 1], ..., a[r - 1], a[r] → a[r], a[l], a[l + 1], ..., a[r - 1].
Count how many numbers equal to k are on the segment from l to r (both borders inclusive).

Fedor hurried to see Serega enjoy the problem and Serega solved it really quickly. Let's see, can you solve it?

Input

The first line contains integer n (1 ≤ n ≤ 10⁵) — the number of elements of the array. The second line contains n integers a[1], a[2], ..., a[n] (1 ≤ a[i] ≤ n).

The third line contains a single integer q (1 ≤ q ≤ 10⁵) — the number of queries. The next q lines contain the queries.

As you need to respond to the queries online, the queries will be encoded. A query of the first type will be given in format: 1 l'_i r'_i. A query of the second type will be given in format: 2 l'_i r'_i k'_i. All the number in input are integer. They satisfy the constraints: 1 ≤ l'_i, r'_i, k'_i ≤ n.

To decode the queries from the data given in input, you need to perform the following transformations:

l_i = ((l'_i + lastans - 1) mod n) + 1; r_i = ((r'_i + lastans - 1) mod n) + 1; k_i = ((k'_i + lastans - 1) mod n) + 1.

Where lastans is the last reply to the query of the 2-nd type (initially, lastans = 0). If after transformation l_i is greater than r_i, you must swap these values.

Output

For each query of the 2-nd type print the answer on a single line.

Serega and Fun

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